Add Integers using Pointers in C

#include <stdio.h>
 
int main()
{
   int first, second, *p, *q, sum;
 
   printf("Enter two integers to add\n");
   scanf("%d%d", &first, &second);
 
   p = &first;
   q = &second;
 
   sum = *p + *q;
 
   printf("Sum of entered numbers = %d\n",sum);
 
   return 0;
}

Pascal's Triangle in C programming

   1
  1 1
 1 2 1
1 3 3 1

#include <stdio.h>

long factorial(int);

int main()
{
   int i, n, c;

   printf("Enter the number of rows you wish to see in pascal triangle\n");
   scanf("%d",&n);

   for (i = 0; i < n; i++)
   {
      for (c = 0; c <= (n - i - 2); c++)
         printf(" ");

      for (c = 0 ; c <= i; c++)
         printf("%ld ",factorial(i)/(factorial(c)*factorial(i-c)));

      printf("\n");
   }

   return 0;
}

long factorial(int n)
{
   int c;
   long result = 1;

   for (c = 1; c <= n; c++)
         result = result*c;

   return result;
}

Floyd's Triangle in C programming

1
2 3
4 5 6
7 8 9 10

#include <stdio.h>
 
int main()
{
  int n, i,  c, a = 1;
 
  printf("Enter the number of rows of Floyd's triangle to print\n");
  scanf("%d", &n);
 
  for (i = 1; i <= n; i++)
  {
    for (c = 1; c <= i; c++)
    {
      printf("%d ",a);
      a++;
    }
    printf("\n");
  }
 
  return 0;
}

Fibonacci Series in C programming

#include<stdio.h>
 
int main()
{
   int n, first = 0, second = 1, next, c;
 
   printf("Enter the number of terms\n");
   scanf("%d",&n);
 
   printf("First %d terms of Fibonacci series are :-\n",n);
 
   for ( c = 0 ; c < n ; c++ )
   {
      if ( c <= 1 )
         next = c;
      else
      {
         next = first + second;
         first = second;
         second = next;
      }
      printf("%d\n",next);
   }
 
   return 0;
}

Diamond Pattern in C

  *
 ***
*****
 ***
  *

#include <stdio.h>
 
int main()
{
  int n, c, k, space = 1;
 
  printf("Enter number of rows\n");
  scanf("%d", &n);
 
  space = n - 1;
 
  for (k = 1; k <= n; k++)
  {
    for (c = 1; c <= space; c++)
      printf(" ");
 
    space--;
 
    for (c = 1; c <= 2*k-1; c++)
      printf("*");
 
    printf("\n");
  }
 
  space = 1;
 
  for (k = 1; k <= n - 1; k++)
  {
    for (c = 1; c <= space; c++)
      printf(" ");
 
    space++;
 
    for (c = 1 ; c <= 2*(n-k)-1; c++)
      printf("*");
 
    printf("\n");
  }
 
  return 0;
}

Reverse A Number in C programming

#include <stdio.h>
 
int main()
{
   int n, reverse = 0;
 
   printf("Enter a number to reverse\n");
   scanf("%d", &n);
 
   while (n != 0)
   {
      reverse = reverse * 10;
      reverse = reverse + n%10;
      n       = n/10;
   }
 
   printf("Reverse of entered number is = %d\n", reverse);
 
   return 0;
}

C program Factorial

#include <stdio.h>
 
int main()
{
  int c, n, fact = 1;
 
  printf("Enter a number to calculate it's factorial\n");
  scanf("%d", &n);
 
  for (c = 1; c <= n; c++)
    fact = fact * c;
 
  printf("Factorial of %d = %d\n", n, fact);
 
  return 0;
}

Mindtree Interview Experience

My experience in the mindtree Programming test!

We had gone in to a college where students from different colleges had come.

We had to choose any one of three different programming languages being C,C++, and Java.

I went with my strength and chose C.

The two programs that were given to me were.

1. To implement a function that will take two numbers num1 and num2 where num1 is single digit number and num2 can be assumed to be a larger one. We need to count the number of occurences of num1 in num2.

My logic was pretty simple for this program.

getnumber(int num1,int num2)

{

int rem,a;

while(num2<0)

{

rem=num2%10;

if(num1==rem)

{

a++;

}

num2=num2/10;

}

return(a);

}

2. The second question was a pattern based question. The pattern was :-

Given that N=4

The desired pattern would be:

1*2*3*4

9*10*11*12

13*14*15*16

5*6*7*8

This was kinda tricky for me. I have been trying to crack it but i am open to solutions for this one.